Dylan Baumbach
April 25th, 2022
Reconstruction by: BlueAcidball
5.37
sec
Ao12 
5.41
sec
Solve #12
SQ1
Vandenbergh
(0,-4)/ (3,0)/ (4,-5)/ (-1,-4)/ (6,0)/ (-3,0)/ (-2,0)/ (-3,-3)/ (3,0)/ (2,-2)/ (4,0)/ (2,0)/


cubedb.net
y2 inspection
0-2/-40/-1-2/e'/ CS
-50/M'/f/ OBL Kite/Zero
20/U'/e/D'/10/e/w/e'/56 PBL F/-