Dylan Baumbach
April 25th, 2022
Reconstruction by: BlueAcidball
5.04
sec
Ao12 
5.41
sec
Solve #1
SQ1
Vandenbergh
(1,0)/ (5,-4)/ (-2,-5)/ (0,-3)/ (-1,-4)/ (3,0)/ (0,-5)/ (0,-3)/ (4,-3)/ (0,-4)/ (2,-3)


cubedb.net
-23/-1-2/U'/ CS
13/T/d'/F'/ OBL Inverse Hazard/Inverse Scottie
f/d3/u'/e'/U2/20 PBL Aa/Ua