Dylan Baumbach
January 3rd, 2022
Reconstruction by: BludAcidBall
6.09
sec
Ao12 
5.87
sec
Solve #12
SQ1
Vandenbergh
(0,5)/ (6,-3)/ (-5,4)/ (-1,-4)/ (3,0)/ (-3,-5)/ (3,0)/ (-3,0)/ (4,0)/ (-2,0)/ (0,-1)/ (2,0)/ (-1,0)


cubedb.net
10/-20/01/20/-10/U'/ CS
13/U'/U/M'/u'/U/ OBL 1E
UD2/B/d/D/1-5/5-3 PBL Jb/Y